Added top height, still needs to be refactored + tested.
This commit is contained in:
45
rtv/page.py
45
rtv/page.py
@@ -314,6 +314,23 @@ class Page(object):
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Loop through submissions and fill up the content page.
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"""
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# Case 1. Inverted, hiding the bottom element
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# Case 2. Inverted, hiding or expanding middle elements
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# Case 1+2. Inverted, hiding or expanding elements
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# In both cases the screen jumps and is re-aligned with the selected
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# item at the bottom of the screen. What we need to do is
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# 1.) Grab the height of the top row (subwin.getmaxyx())
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# 2.) Draw the page as non inverted, except for the top element. This
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# element will be drawn as inverted with the smaller height
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# 3.) If expanding and the bottom element also doesn't fit, redraw
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# everything inverted as normal.
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# 4.) Otherwise, this should ensure that the bottom element is always
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# full visible and the cursor doesn't jump lines.
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# Note: Should also disable drawing inverted if only one element
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# Note: If only one comment, add (Not enough space to display)
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n_rows, n_cols = self.term.stdscr.getmaxyx()
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window = self.term.stdscr.derwin(
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n_rows - self._row, n_cols, self._row, 0)
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@@ -327,29 +344,41 @@ class Page(object):
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# If not inverted, align the first submission with the top and draw
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# downwards. If inverted, align the first submission with the bottom
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# and draw upwards.
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cancel_inverted = True
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current_row = (win_n_rows - 1) if inverted else 0
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available_rows = (win_n_rows - 1) if inverted else win_n_rows
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top_height = self.nav.top_height if not inverted else None
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for data in self.content.iterate(page_index, step, win_n_cols - 2):
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subwin_n_rows = min(available_rows, data['n_rows'])
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if top_height:
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subwin_n_rows = min(subwin_n_rows, top_height)
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subwin_n_cols = win_n_cols - data['offset']
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start = current_row - subwin_n_rows if inverted else current_row
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subwindow = window.derwin(
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subwin_n_rows, subwin_n_cols, start, data['offset'])
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attr = self._draw_item(subwindow, data, inverted)
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self._subwindows.append((subwindow, attr))
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attr = self._draw_item(subwindow, data, top_height or inverted)
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self._subwindows.append((subwindow, attr, subwin_n_rows))
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available_rows -= (subwin_n_rows + 1) # Add one for the blank line
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current_row += step * (subwin_n_rows + 1)
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top_height = None
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if available_rows <= 0:
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# Indicate the page is full and we can keep the inverted screen.
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cancel_inverted = False
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break
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else:
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# If the page is not full we need to make sure that it is NOT
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if len(self._subwindows) == 1:
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# Never draw inverted if only one subwindow. The top of the
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# subwindow should always be aligned with the top of the screen.
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cancel_inverted = True
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if cancel_inverted and self.nav.inverted:
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# In some special cases we need to make sure that the screen is NOT
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# inverted. Unfortunately, this currently means drawing the whole
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# page over again. Could not think of a better way to pre-determine
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# if the content will fill up the page, given that it is dependent
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# on the size of the terminal.
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if self.nav.inverted:
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self.nav.flip((len(self._subwindows) - 1))
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self._draw_content()
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self.nav.flip((len(self._subwindows) - 1))
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self._draw_content()
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self._row = n_rows
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@@ -387,7 +416,7 @@ class Page(object):
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if self.nav.cursor_index >= len(self._subwindows):
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self.nav.cursor_index = len(self._subwindows) - 1
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window, attr = self._subwindows[self.nav.cursor_index]
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window, attr, _ = self._subwindows[self.nav.cursor_index]
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if attr is not None:
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attribute |= attr
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